What is (jk)(x) when j(x)=-7x and k(x)=9-2x
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Answer:
Step-by-step explanation:
Hello There!
Once again we are going to use trigonometry to solve for x
Here are the <u>Trigonometric Ratios</u>
sin = opposite divided by hypotenuse
cos = adjacent divided by hypotenuse
tan = opposite divided by adjacent
we need to find x and we are given its opposite side length (58) and the adjacent side length (19)
this corresponds with tangent so once again we will be using tangent to solve for x
Looking at tangent we see that its equal to opposite divided by adjacent so we create an equation
now we have
Once again we need to get rid of the tan
to do so we take the inverse of tan ( tan^-1) and apply it to each side
finally we round to the nearest tenth
we're left with x = 71.9