We want to find the value of cot(θ) given that sin(θ) = 3/8 and θ is an angle in a right triangle, we will get:
cot(θ) = (√55)/3
So we know that θ is an acute angle in a right triangle, and we get:
sin(θ) = 3/8
Remember that:
- sin(θ) = (opposite cathetus)/(hypotenuse)
- hypotenuse = √( (opposite cathetus)^2 + (adjacent cathetus)^2)
Then we have:
opposite cathetus = 3
hypotenuse = 8 = √(3^2 + (adjacent cathetus)^2)
Now we can solve this for the adjacent cathetus, so we get:
adjacent cathetus = √(8^2 - 3^2) = √55
And we know that:
cot(θ) = (adjacent cathetus)/(opposite cathetus)
Then we get:
cot(θ) = (√55)/3
If you want to learn more, you can read:
brainly.com/question/15345177
Answer:
Let pork chops and ground beef be x and y respectively.
4x = $12.60
x = $3.15
11x = $34.65
5y = $10.25
y = $2.05
12y = $24.60
11x + 12y = $34.65 + $24.60
= $59.25
You'd solve this equation by writing two equations. I'd call treadmills x and stationary bikes as y. The two equation would be x+y=25 and y=x+7. You'd then plug the second equation into the first equation to get x+(x+7)=25. You'd combine like terms, making it 2x+7=25. You'd then subtract 7 from both sides to get 18 and divide that by 2 to get 9. You have 9 treadmills. Finally, you'd plug 9 in for x in the equation y=x+7, to get 16 for stationary bikes.
Answer:
533.33 ft/min
Step-by-step explanation:
We are given that
x=3 feet
y=4 feet
Height of person,h=6 feet
Triangle ABC and A'B'C are similar because all right triangles are similar
By using similarity property
Differentiate w.r.t t
Hence, If the person is 6 feet tall and walks away from the lamp post at a speed of 400 feet per minute then his shadow moving at the rate 533.33 ft/min
18j + 32w = $19.92
14j + 26w = $15.76
HAVE A GREAT DAY MA DUDE!
