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3 years ago

Suppose a solitaire player played 1000 games. Predict how many times the player turned over a red card as the first card

Mathematics

1 answer:

Viktor [21]3 years ago

4 0

I would predict about 50-200 Times

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John bought a video game that was 20% off. The game was originally $30. How much money DID HE SAVE by getting it on sale?

geniusboy [140]

Answer:

Step-by-step explanation:

when you multiply $30 by 20% you get 6. 30-6= $24 after the 20% is taken off, but he saved $6.

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2 years ago

What is an example of a non-statistical question? Question 1 is because of winn dixie your favorite book

lozanna [386]

Answer:

examples of non-statistical questions are: how old are you?

Step-by-step explanation:

Non-Statistical Questions. The next type of question is the non-statistical question. This is the type of question that only has one answer. This one answer also doesn't change. You don't need to gather several points of data to answer the question.

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3 years ago

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45<br> 2<br> If<br> = 2, what is the value of<br> A) O<br> B) 1<br> C) 2<br> D) 4.

eimsori [14]

Answer:

Tangent = opposite / adjacent

Tangent of 45º equals 1

Step-by-step explanation:

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2 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

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7 months ago

PLZ HELP!!!! WILL MARK BRAINLIEST!!!!

Yuliya22 [10]

Answer:

2 $a^{3} b^{5$

Step-by-step explanation:

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2 years ago

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