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4 years ago

Simplify the following expression. 4(20+12) divided by (4-3)

2 answers:

7 0

4(20+12)/(4-3) = 4(32)/1 = 128
Use order of operations (PEMDAS) Please Excuse My Dear Aunt Sally, and solve for parantheses, then multiply parentheses and then divide by 1.

nekit [7.7K]4 years ago

7 0

Answer:

The answer to the equation is 128.

Step-by-step explanation:

Simplify the following expression:

$4(20+12)$ divided by $(4-3)$

$4(20+12)$ = $4(32)$ = 128

$(4-3)$ = 1

So, $\frac{4(20+12)}{4-3}$

= $\frac{128}{1}=128$

So, the answer to the equation is 128.

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5. Anthony owns a business that sells parts for electronic game systems. The profit for his business can be

Ronch [10]

Solution given:

p(x)=0

-0.2x2 + 10x – 25=0

-0.2(x²-50x+125)=0

x²-2.25.x+25²=25²-125

(x-25)²=500

x-25= $\sqrt{500}$

x-25=±10√5

taking positive

x=22.3606+25

x=47.3606

taking negative

x= -22.3606+25

x=2.639

maximum profit Anthony will receive :47.3606*1000= 47360600(approach)

now

47360 .6 or 2639 parts he would need to sell to receive the maximum profit

3 0

3 years ago

The given equation has been solved in the table.

insens350 [35]

Answer:

D. the subtraction property of equality was not applied.

Step-by-step explanation:

Step 1: Listed the statement

Step 2: applied the addition property of equality

Step 3: Simplified

Step 4: Applied the multiplication property of equality

Step 5: Simplified

7 0

3 years ago

If we sample from a small finite population without replacement, the binomial distribution should not be used because

Nezavi [6.7K]

Using the hypergeometric distribution, it is found that there is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

For this problem, the parameters are given as follows:

N =A + B = 54, k = 4, n = 4.

The probability of getting exactly two winning numbers with one ticket is P(X = 2), hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,54,4,4) = \frac{C_{4,2}C_{50,2}}{C_{54,4}} = 0.0232$

There is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

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3 0

2 years ago

3/10 multiply to find an equivalent fraction

SCORPION-xisa [38]

You multiply both the numerator and the denominator by the same number (but not 1 or 0), but don't simplify. 3/10 is your fraction, and you could multiply the top and bottom numbers by 2 to get 6/20.

I hope I helped please leave thanks

8 0

3 years ago

What is the missing length of the polygon shown below if the perimeter is 32 m

Artyom0805 [142]

Answer:

Step-by-step explanation:

2+4+3+4+3+4+5=25

32-25=7

6 0

2 years ago

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