Answer:
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Given:
<span>Graph of line W going through ordered pairs negative 4, negative 2 and negative 1, 5.
Graph of line X going through ordered pairs negative 2, negative 1 and 0, 5.
Graph of line Y going through ordered pairs negative 1, negative 3 and 1, 3.
Graph of line Z going through ordered pairs 0, negative 5 and 2, 1
Slope formula: m = y2-y1 / x2 - x1
mW = 5 - (-2) / -1 - (-4) = 5 + 2 / -1+ 4 = 7 / 3 = 2 1/3
mX = 5 - (-1) / 0 - (-2) = 5 + 1 / + 2 = 6 / 2 = 3
mY = 3 - (-3) / 1 - (-1) = 3 + 3 / 1 + 1 = 6 / 2 = 3
mZ = 1 - (-5) / 2 - 0 = 1 + 5 / 2 = 6 /2 = 3
</span><span>f(x) = 3x + 5
X: </span><span>negative 2, negative 1 and 0, 5
f(-2) = 3(-2) + 5 = -6 + 5 = -1
f(0) = 3(0) + 5 = 0 + 5 = 5
Y: </span><span>negative 1, negative 3 and 1, 3
f(-1) = 3(-1) + 5 = -3 + 5 = 2 </span>≠ -3<span>
f(1) = 3(1) + 5 = 3 + 5 = 8 </span>≠ 3
Z: <span>0, negative 5 and 2, 1
f(0) = 3(0) + 5 = 0 + 5 = 5 </span>≠ -5
f(2) = 3(2) + 5 = 6 + 5 = 11 ≠ 1
<span>LINE X is represented by the function f(x) = 3x + 5</span>
5y - 20 < 0...add 20 to both sides
5y < 20...divide both sides by 5
y < 20/5
y < 4 (this states that y is less then 4)
Therefore, the greatest integer that y could be is 3 (because integers cannot be fractions, they have to be whole numbers)
You would write it out 7.83
Answer: Draw rectangle put 149m at the top and bottom and 76m at the side now add and you 450m
