Answer:
37 minutes
Step-by-step explanation:
Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Answer:324
Step-by-step explanation:
int i = 42.7; /* konwersja z double do int */
float f = i; /* konwersja z int do float */
double d = f; /* konwersja z float do double */
unsigned u = i; /* konwersja z int do unsigned int */
f = 4.2; /* konwersja z double do float */
i = d; /* konwersja z double do int */
char *str = "foo"; /* konwersja z const char* do char* [1] */
const char *cstr = str; /* konwersja z char* do const char* */
void *ptr = str; /* konwersja z char* do void* */
Podcza
Hello,
P(x)=x^3-7x-6
P(4)=4^3-7*4-6=30
Remainder=30
Answer:
6 minutes
Step-by-step explanation:
15-5=10
10-4=<u>6</u>
