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Jobisdone [24]
3 years ago
12

Find the value of x

Mathematics
1 answer:
geniusboy [140]3 years ago
7 0

-1, maybe or maybe not this is my first time doing this

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Show that the equation x^3 + x -3 =0 has a solution between 1 and 2. That is the only information given
valentina_108 [34]

Answer:

Step-by-step explanation:

Given that:

f(x) = x^3 + x - 3 = 0

Since the given function is equal to zero, then the function :

f(x) = x^3 + x - 3

where;

x = 1 and

x = 2

f(x) = (1)^3 + (1) - 3 \\  \\ f(x) = 1 + 1 - 3 \\ \\f(x) = -1 < 0

f(2) =  x^3 + x - 3 \\ \\f(2) = (2)^3 + 3 - 3  \\ \\f(2) = 8 + 3 - 3  \\ \\f(2) = 11 - 3 \\ \\f(2) = 8 > 0 \\ \\

Thus; f(1) < 0 and f(2) > 0

8 0
2 years ago
Write the percent as a fraction or mixed number in simplest form. <br> 62%
suter [353]
= 62%

= 0.62

= 62/100

= 31/50

6 0
3 years ago
Read 2 more answers
Quadrilateral EFGH has coordinates E(2a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of he
Gre4nikov [31]
The formula of the midpoint of HE:
\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)

We have H(0; 0) and E(2a; 2a). Substitute:
\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)

4 0
3 years ago
Read 2 more answers
the number of patients treated dr. martens dentist office each day was recorded for nine days. These are the data; six, six, six
Effectus [21]

Answer:

Mean: 5.5555555555556

Median: 6

Mode: 6

Step-by-step explanation:


8 0
2 years ago
a. For what values of x does f (x )equals 3 x plus 3 sine x have a horizontal tangent​ line? b. For what values of x does f (x )
laila [671]

Answer:

(a)Therefore the value of x=\pi

(b) Therefore the value of x =\frac{\pi}{2}

Step-by-step explanation:

Horizontal tangent line: The first order derivative of a function gives the slope of the tangent of the function. The slope of horizontal line is zero.If the slope of tangent line is zero then the tangent line is called horizontal tangent line.

(a)

Given function is,

f(x)= 3x+3sin x

Differential with respect to x

f'(x)=3+3cos x

For horizontal tangent line, f'(x)=0

3+ 3 cos x= 0

⇒3 cos x=-3

⇒cos x=-1

⇒x = 180° =\pi

Therefore the value of x=\pi

(b)

Given that, the slope is 3.

Then,f'(x)=3

3+ 3 cos x= 3

⇒3 cos x= 3-3

⇒cos x=0

⇒x = 90° =\frac{\pi}{2}

Therefore the value of x =\frac{\pi}{2}

5 0
2 years ago
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