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pochemuha
3 years ago
11

Write an equation in point-slope form that has a slope of -1/2 and a y-intercept of -8.

Mathematics
2 answers:
victus00 [196]3 years ago
8 0
Point slope form is y-y1=m(x-x1)

M is the slope
y1 and x1 come from the point given

Answer:
Y+8=1/2(x-0)

If it should be simplified y+8=1/2x

The x value is 0 because when the line intercepts the y axis x=0
BlackZzzverrR [31]3 years ago
7 0

9514 1404 393

Answer:

  y +8 = -1/2x

Step-by-step explanation:

The point-slope form of the equation for a line is ...

  y -k = m(x -h) . . . . . . . line through point (h, k) with slope m

__

The y-intercept point has an x-coordinate of 0, so that point is (0, -8). Filling in the values (h, k) = (0, -8) and m = -1/2 in the above form gives ...

  y +8 = -1/2x . . . . . point-slope form of the equation

_____

<em>Additional comment</em>

Normally, given a slope and a y-intercept, you would use the slope-intercept form:

  y = mx +b . . . . . . line with slope m and y-intercept b

  y = -1/2x -8

You will notice the two forms of the equation are just different forms of the same thing. If you add 8 to both sides of the slope-intercept equation, you get the point-slope equation.

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Step-by-step explanation:

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<h2><u>Answer with explanation:</u></h2>

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What was the age distribution of prehistoric Native Americans? Extensive anthropological studies in the southwestern United Stat
neonofarm [45]

Answer:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{1394}{88}=15.8

s^2 = \frac{88(32372) -(1394)^2}{88(88-1}=118.3

Sd(X) = \sqrt{118.273}=10.9

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.  

Solution to the problem

For this case we can calculate the properties required with the following table:

Interval     Mid point (x)     f           x*f         x^2 *f

_________________________________________

1-10               5.5               40        220         1210

11-20             15.5              15        232.5       3603.75

21-30            25.5             23       586.5       14955.75

>31                35.5             10        355          12602.5

________________________________________

Total                                 88        1394         32372

We assume that the mid point for the class >31 is 35.5 using the problem information.

For this case the expected value would be given by:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{1394}{88}=15.8

The variance owuld be given by this formula"

s^2 = \frac{n(\sum x^2 f) -(\sum xf)^2}{n(n-1}

And if we replace we got:

s^2 = \frac{88(32372) -(1394)^2}{88(88-1}=118.3

The standard deviation would be just the square root of the variance:

Sd(X) = \sqrt{118.273}=10.9

4 0
3 years ago
Read 2 more answers
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