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White raven [17]
3 years ago
6

X+Y-Z=19 2X-3Y+Z=13 3X-5Y-6Z=-15

Mathematics
1 answer:
lawyer [7]3 years ago
7 0

A suitable graphing caculator gives the result

X = 15 25/39

Y = 7 6/13

Z = 4 4/39

_____

If you want to solve this by hand, you can add 3 times the first equation to the second to get

... 5X -2Z = 70

and 5 times the first equation to the third to get

... 8X -11Z = 80

Then Cramer's Rule tells you the solutions for X and Z are

... X = (-160+770)/(-16+55) = 610/39

... Z = (560 -400)/39 = 160/39

From there, you can substitute into any of the equations to find Y. The first one might be most convenient.

... Y = 19 -X +Z = 19 -(15 25/39) +(4 4/39) = 8 -21/39 = 7 6/13

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3 years ago
Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5
MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

5 0
3 years ago
Which is greater, 13/35 or 2/5?
zhenek [66]
Hi there!

If you run into problems like this, remember to "Stay calm and find the common denom." That just means find the common denominator.

13/35 and 2/5 = 13/35 and 14/35

As you can tell, 2/5 is larger.

Hope this helps.

:)
5 0
3 years ago
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