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Ipatiy [6.2K]
3 years ago
14

Janice bought 2 gifts yesterday. The price of one gift was 3 times the cost of the other. If both gifts cost $25.60 altogether,

how much was each gift.
Mathematics
2 answers:
Ilya [14]3 years ago
8 0

Answer: the prices of the gifts are $6.4 and $19.2

Step-by-step explanation:

Let x represent the price of the cheaper gift.

Let y represent the price of the costlier gift.

The price of one gift was 3 times the cost of the other. It means that the price of the costlier gift is expressed as

y = 3x

If both gifts cost $25.60 altogether, it means that

x + y = 25.60- - - - - - - -- - -1

Substituting y = 3x into equation 1, it becomes

x + 3x = 25.6

4x = 25.6

x = 25.6/4

x = $6.4

y = 3x = 3 × 6.4

y = $19.2

Ahat [919]3 years ago
5 0

Answer:

one gift was $6.40 and the other was $19.20

Step-by-step explanation:

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<h3>Answer:  d. Contingency table</h3>

Explanation:

It's most effective to use a contingency table because we have two variables here: 1) the responses, and 2) the party affiliation.

We can have the responses along the rows and the party affiliation along the columns, or vice versa.

See the example below. The values are completely random simply for the purpose of the example (and not drawn from any real life data source).

6 0
3 years ago
2
Fed [463]
It could be 4?? I could be wrong tho, sorry if I am!
8 0
3 years ago
As shown on the diagram, a regular pyramid has a square base whose side measures 6 inches. If the altitude of the pyramid measur
Elza [17]

Answer:

144 in³

Step-by-step explanation:

The volume of a pyramid of base area A and height h is

V = (1/3)(A)(h).

Here,

V = (1/3)(6 in)²(12 in) = 144 in³

4 0
3 years ago
Fist answer gets brain
Misha Larkins [42]
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5 0
3 years ago
Read 2 more answers
What two numbers can add to 4 but multiple to -12
olasank [31]

Answer:

<em>Numbers: 6 and -2</em>

Step-by-step explanation:

<u>Equations</u>

This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.

However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:

x+y=4\qquad\qquad [1]

x.y=-12\qquad\qquad [2]

Solving [1] for y:

y=4-x

Substituting in [2]

x(4-x)=-12

Operating:

4x-x^2=-12

Rearranging:

x^2-4x-12=0

Solving with the quadratic formula:

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

With a=1, b=-4, c=-12:

\displaystyle x=\frac{-(-4)\pm \sqrt{(-4)^2-4(1)(-12)}}{2(1)}

\displaystyle x=\frac{4\pm \sqrt{16+48}}{2}

\displaystyle x=\frac{4\pm 8}{2}

The solutions are:

\displaystyle x=\frac{4+ 8}{2}=6

\displaystyle x=\frac{4- 8}{2}=-2

This confirms the preliminary results.

Numbers: 6 and -2

7 0
3 years ago
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