Question

The equation of the graphed line in slope point form using the point (2,-1 ) is blank and it’s equation in slope intercept is blank

Answer 1

Answer:

$y=\frac{1}{4}x-\frac{3}{2}$ (Slope intercept form)

$y+1=\frac{1}{4}(x_-2)$ (Slope point form)

Step-by-step explanation:

The slope of the line can be calculated as following:

$m=\frac{-1-(-2)}{2-(-2)}=1/4$

The the equation of the line in slope point form is:

$y-y_1=m(x_-x_1)$

Where ($x_1$,$y_1$) is a point of the line.

Then you must susbtitute the point given and the slope and you obtain:

$y+1=\frac{1}{4}(x_-2)$

The intercept form is:

$y=mx+b$

Where b is the y-intercept.

Solve for y from the equation of the line in slope point form obtained above, then:

$y+1=\frac{x}{4}-\frac{2}{4}\\y=\frac{1}{4}x-\frac{2}{4}-1\\y=\frac{1}{4}x-\frac{3}{2}$