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3 years ago

What's the domain of this function graph?

Mathematics

1 answer:

Mkey [24]3 years ago

3 0

The graph may continue to the left and right beyond what is viewed, but based on the portion of the graph that is visible, we can determine the domain as 1973 ≤ t ≤ 2008 1973 ≤ t ≤ 2008 and the range as approximately 180 ≤ b ≤ 2010 180 ≤ b ≤ 2010.

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Can you answer this please ?

chubhunter [2.5K]

Answer: 91

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3 years ago

50×60×8000 f(x)=4000× f (y)=

Aloiza [94]

Answer:

9,600,000,000 F (y)=5000

Step-by-step explanation:

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4 0

3 years ago

The united states mint released five state quarters every year. there are 50 states. How many years did it take for all 50

Gekata [30.6K]

You divide 50/5=10 years.

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3 years ago

In a village, there was an epidemic and the population decreased by 10%. If there were only 1800 people left in the village, wha

tester [92]

$\bold{\boxed{\huge{\blue{\underline{Answer }}}}}$

$\bold{\underline{ Given :- }}$

$\sf{The\: population\: is\: decreased \:by\: 10 percent }$

$\sf{There\: were \: only \: 1800 \: people \: left}$

$\bold{\underline{ To\: Find :- }}$

$\sf{we \: have \: to \: find\: original \: population? }$

$\bold{\underline{ Let's \: Begin :- }}$

$\sf{Let \: the \: total \: population\: be \: x }$

$\sf{\underline{ Therefore }}$

$\sf{According \: to \: the \: question }$

$\sf{ x - 10/100 = 1800 }$

$\sf{ 100x - 10/100 = 1800}$

$\sf{ 100x - 10 = 1800 × 100}$

$\sf{100x - 10 = 180000}$

$\sf{ 100x = 180000 + 10}$

$\sf{ x = 180010/100}$

$\sf{ x = 1800.1 }$

$\bold{\pink{Hence , The\: original \:population \:of \: the\: village \:is \:1800.1 }}$

7 0

2 years ago

A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat

LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0

2 years ago