Answer:
Step-by-step explanation:
Draw a line from S to T'
T' is where the angle PTQ intersects the circle when SR is extended so that it hits the circumference of the circle.
This line bisects the 50 degree angle (which is given. It also bisects PRS.
y is shown on the diagram.
Your first job is to find y
It's y + 90 + 25 = 180 because all triangles are made up of 180 degrees.
y it turns out is 65 degrees.
Now comes the interesting part. PRT' is supplementary to y. It is labeled as 180 - y
<PRT' + Y = 180
y = 65
<PRT' = 180 - 65 = 115
Since PRT' = 115 and since PR = PT' (They are both radii). x/2 + x/2+ 115 = 180 I'll talk about x/2 down below this.
x + 115 = 180 All triangles = 180
x = 65.
Where did x/2 come? As long as PTQ is situated on the arc that it is on then <PTQ is always going to be x. You will have to piece together the two diagrams to make this work.i
It's a very good application of circles and lines well worth your time to get to know.
Answer:
false
Step-by-step explanation:
the are of a shape will always be greater than the perimeter
Need more info about the 3 younger siblings
the solutions to the related equation are 0,2,3 .
<u>Step-by-step explanation:</u>
Here we have , function f(x) = x3 – 5x2 + 6x . Graph of this function is given below . We need to find What are the solutions to the related equation . Let's find out:
Solution of graph means the value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !
At x = 0 .
From the graph , at x=0 we have f(x) = 0 i.e.
⇒
⇒
⇒
At x = 2 .
From the graph , at x=2 we have f(x) = 0 i.e.
⇒
⇒
⇒
At x=3 .
From the graph , at x=3 we have f(x) = 0 i.e.
⇒
⇒
⇒
Therefore , the solutions to the related equation are 0,2,3 .
Answer:
Between -12 and -13, decimal estimate: -12.2
Step-by-step explanation:
First let's disregard the negative sign, and focus on . The smallest square below it is , or 144. The greatest square right above it is , or 169.
Now we know that is somewhere between 12 and 13. Likewise is between -12 and -13. If 12.5 is the square root of 150, it is too high, so we reduce it to 12.2 to 12.3.
Then we can just negate our answer, since we are looking for , to get about -12.2.