Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
Answer:
I believe it's 24 combinations.
Step-by-step explanation:
I found how many there were when starting with English, and there were six. I multiplied this by four (for the four books) and found 24.
Hope this helps! Have a nice day :)
Answer:
can i please have more details please?
Step-by-step explanation:
To do this you times 3 by 4 and add it on to the numerator of the fraction, to turn it into a top heavy fraction:
3*4 = 12
1+12/3 = 13/3
Then you multiply the numerator by 21 to work out what 21 times the fraction is:
13*21/3 = 273/3
Then you can divide 273 by 3 to get the final answer:
273/3 = 91
He will have 91 peaches overall.
Hope this helps! :)