B=number of ticets sold before
a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a
total cost=925000
39.95b+54.95a=925000
total number tickets=20000
b+a=20000
we have
39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000
15a=126000
divide bot sides by 15
a=8400
sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600
11,600 tickets sold before
8400 tickets sold after
Answer:
whats the question?
Step-by-step explanation:
Hey the answer is 2713 cm
Answer:

Step-by-step explanation:
<u>Step 1: Multiply
</u>




Answer: The correct answer is -1
Answer:
The first one
Step-by-step explanation:
An easy way is SOH CAH TOA
SOH is that you use sine if you there is the opposite (in this case the question mark) and hypotenuse (the diagonal line)
CAH is that you use cosine for the adjacent side (1100) and the hypotenuse.
TOA is using tangent for the opposite and adjacent side.
To fine the question mark, you would use tangent. And plug in the given (1100 for the adjacent). So tan45 = x/1100.
If you need more help or clarification, let me know!