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Illusion [34]
3 years ago
15

Estimate the quotient for 469.4÷62​

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0

Answer:

469.4/62=7.57

Step-by-step explanation:

its the correct answer

rosijanka [135]3 years ago
4 0

Answer:

8.0 is the answer

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In 1.8 s, a smart and swift dachshund caught his prey that was 8.5 m away what was the dogs speed?​
Paul [167]
The answer is 11 miles per hour
8 0
3 years ago
What is an simplified expression for 8a-(-3-5a)-2a?
bogdanovich [222]

Answer:

The answer is 11a+3

Step-by-step explanation:

Simplify the terms.

8a+3+5a-2a

Combine like terms.

8a+5a-2a=11

11a+3

7 0
3 years ago
To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data
nexus9112 [7]

Answer:

a) \sigma = 0.167

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of \mu. So X - \mu = 0.5 must have Z = 3 and X - \mu = -0.5 must have Z = -3.

So

Z = \frac{X - \mu}{\sigma}

3 = \frac{0.5}{\sigma}

3\sigma = 0.5

\sigma = \frac{0.5}{3}

\sigma = 0.167

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that \sigma = 2.8

The standard deviation of a sample of n young man is given by the following formula

s = \frac{\sigma}{\sqrt{n}}

We want to have s = 0.167

0.167 = \frac{2.8}{\sqrt{n}}

0.167\sqrt{n} = 2.8

\sqrt{n} = \frac{2.8}{0.167}

\sqrt{n} = 16.77

\sqrt{n}^{2} = 16.77^{2}

n = 281.23

We need a sample of at least 282 young men.

6 0
3 years ago
How to draw a drawing graph?
Lapatulllka [165]
Make a horizontal line on the paper. You may draw arrows on the ends of the line to indicate it is a number line that continues past your data sample. Put the label "X" to the right of the line to indicate the x axis. Mark the center of the line with a vertical tick mark and label it 0. This is the origin of the graph. Make equally spaced tick marks on the rest of the x axis. For this example you should label the tick marks from 1 to 10 on the right side of the 0.
5 0
3 years ago
How do I solve 321-207=342
artcher [175]
321-207 is actually equals to 114 but I mean the equation is false
8 0
3 years ago
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