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neonofarm [45]
3 years ago
8

Complete the table and then determine which of the following is the graph of f (x) =ƒ(x) = 3√x + 2 + 4..

Mathematics
2 answers:
satela [25.4K]3 years ago
5 0
F(-2)=4
f(-1)=5
f(-3)=3
f(6)=6
f(-6)=2

first graph is answer
Alenkinab [10]3 years ago
4 0

Answer:

The given function is

  f(x)=3\sqrt{x+2}+4\\\\y=3\sqrt{x+2}+4

Taking x as an independent variable , and y as a dependent variable we can calculate,few y values for some x values, and then find the required graph.

 1.→For, x=-2

y=3 × 0 +4

y=4

Point=(-2,4)

2.→For, x=7

 y=3\times \sqrt{2+7}+4\\\\y=3\times 3+4\\\\y=13

Point=(7,13)

→If you will look at Graph A, it passes through (-2,4) as well as (7,13).

Option A----Graph A

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Find equation of the line that contains the point (4,-2) and is perpendicular to the line y= _2x+8
xz_007 [3.2K]

Answer:

y = 1/2x - 4

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = -2x + 8. Its slope is -2. A line perpendicular to this one will  have a slope of 1/2.

Plug this value (1/2) into your standard point-slope equation of y = mx + b.

y = 1/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (4, -2). Plug in the x and y values into the x and y of the standard equation.

-2 = 1/2(4) + b

To find b, multiply the slope and the input of x (4)

-2 = 2 + b

Now, subtract 2 from both sides to isolate b.

-4 = b

Plug this into your standard equation.

y = 1/2x - 4

This equation is perpendicular to your given equation (y = -2x + 8) and contains point (4, -2)

Hope this helps!

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Answer:

B.

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