Answer:
11.28 ft
Step-by-step explanation:
The volume of a cylinder can be written as;
Volume V1 = πr^2 h
The volume of an hemisphere can be written as;
Volume V2 = (2/3)πr^3
The total volume of the silo is;
V = V1 + V2
V = πr^2 h + (2/3)πr^3
Given;
Volume of silo V= 15000 ft^3
Height of cylinder part h = 30 ft
Substituting the values;
V = πr^2 h + (2/3)πr^3
15000 = 30πr^2 + (2/3)πr^3
15000/π = 30r^2 + (2/3)r^3
2r^3 + 90r^2 - (15000×3/π) = 0
Solving the equation, we have;
r = 11.28 ft or -15.61 ft or -40.67 ft
Since the radius cannot be negative;
Radius r = 11.28 ft
Answer:
10.92cm
Step-by-step explanation:
We can solve this problem by taking the formula to the area of a triangle and substituting our given numbers with the variables in it.
, where 
represents base and 
represents height.
So, if we substitute our given measurements with the variables in this formula, we can easily solve this.
Then, using the order of operations, we multiply and ultimately solve this problem.
Thus, our answer is 10.92cm.
Answer:
the answers to this are x= 1 and y= 9
Answer:
90 cents
Step-by-step explanation
divide .99 by 10 and that gets you 9 cents minus that off and its 90 Cents
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
