Step-by-step explanation:
sinA= BC/AC
= 24/26
= 12/13
cosA= AC/AB
= 10/26
= 5/13
tanA= BC/AC
=24/10
= 12/5
Answer:
Step-by-step explanation:
5(x)-600=800
x=280
Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
Step-by-step explanation:
4/5a*3/2a^2
4*3/5a*2a^2
12/10a^3
6/5a^3
therefore ur answer is 6/5a^3
Answer:
149 degrees
Step-by-step explanation:
<u>Higher value: </u>
114
<u>Lower value:</u>
-35
<u>Finding the difference:</u>
114 - (-35)
114 + 35
149