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victus00 [196]
4 years ago
8

HELLLLLPPPPPP

Mathematics
1 answer:
aleksley [76]4 years ago
8 0
(3p, x+4) Is what I'm gonna go for.
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How do i do this? the interquartile range? please help!
Irina18 [472]

Answer:

20

Step-by-step explanation:

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4 years ago
Please help me please I don’t understand and my teacher said I got it wrong for numbers 1 2 and 3
kirza4 [7]

Answer:

1) 5/9

2) 4/7

3) 3/8

Step-by-step explanation:

1) 5/9

2) 4/7

3)3/8

3 0
3 years ago
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Starting at 6 a.m. every morning, Matilda receives text messages on her cell phone from her mother, her best friend, and her bro
Dafna1 [17]

Answer:

a) 0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

b) 1.6 \times 10^{-9} probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A) Find the probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

Two from the best friend:

Her best friend sends a message once every 10 minutes.

From 6 to 7:30, there is an hour and a half, that is, 90 minutes, so the mean for her best friend is \mu = \frac{90}{10} = 9

Two messages is P(X = 2). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-9}*9^{2}}{(2)!} = 0.0050

Two from the mother:

Message every hour = 60 minutes. So \mu = \frac{90}{60} = 1.5. This is P(X = 2).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-1.5}*1.5^{2}}{(2)!} = 0.2510

Two of her best friend and two of her mother:

Independent events, so the probability of both happening is the multiplication of their separate probabilities.

p = 0.005*0.251 = 0.0013

0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

B) With a chance of 75% a text message contains a typo independent of the sender. Find the probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

In 3 hours, she is expected to receive:

3*60/10 = 18 messages from her best friend.

3*60/60 = 3 messages from her mother.

3*60/30 = 6 messages from her brother.

In total, 27 messages.

75% probability of a typo, so \mu = 0.75*27 = 20.25

This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20.25}*20.25^{0}}{(0)!} = 1.6 \times 10^{-9}

1.6 \times 10^{-9} probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

8 0
3 years ago
What is the mode range maximum minimum median of the numbers 3,4,3,2,3,4,5,2
Ymorist [56]
Mode: 3
Maximum: 5
Minimum: 2
Median: 3
( the range is a decimal )
6 0
3 years ago
a circular pizza with a diameter of 10 inches is cut into 6 equal slices. what is the area of each slice?
aalyn [17]
Hello

I believe each slice would be about 5.236 in. area


Hope this helps :D
5 0
3 years ago
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