Question

The sum of two consecutive even intergers divided by four is 189.5

Answer 1

Let n be the first integer, then n+2 is the following integer. Then,

(n+n+2)/4=189.5

Solve the equation to find n=378

Answer 2

189.5= (n+n)÷4 you would set up sort of like a proportion to solve
189.5 = (n+n)÷4. you would divide each side by 4 because you are doing pemdas backwards so 189.5÷4= 47.37
47.37 = n+n
and you know n and n are the same so divide 47.37 by 2 to get 23.68
23.68=n