There are 3 in. of snow on the ground when it begins to snow 0.5 in. /h.

According to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not

Fynjy0 [20]

Using the binomial distribution, it is found that:

a) There is a 0.0162 = 1.62% probability that among 12 randomly observed individuals, exactly 7 do not cover their mouth when sneezing.

b) There is a 0.5958 = 59.58% probability that among 12 randomly observed individuals, fewer than 5 do not cover their mouth when sneezing.

c) The probability is higher than 5%, so it would not be unusual.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, with p probability.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem:

Sample of 12, thus $n = 12$
0.267 probability that a person covers their mouth, thus $p = 0.27$ .

Item a:

This probability is P(X = 7), so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{12,7}.(0.267)^{7}.(0.733)^{5} = 0.0162$

There is a 0.0162 = 1.62% probability that among 12 randomly observed individuals, exactly 7 do not cover their mouth when sneezing.

Item b:

The probability is P(X < 4), which is:

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.267)^{0}.(0.733)^{12} = 0.0241$

$P(X = 1) = C_{12,1}.(0.267)^{1}.(0.733)^{11} = 0.1052$

$P(X = 2) = C_{12,2}.(0.267)^{2}.(0.733)^{10} = 0.2107$

$P(X = 3) = C_{12,3}.(0.267)^{3}.(0.733)^{9} = 0.2558$

Then

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0241 + 0.1052 + 0.2107 + 0.2558 = 0.5958$

There is a 0.5958 = 59.58% probability that among 12 randomly observed individuals, fewer than 5 do not cover their mouth when sneezing.

Item c:

This probability is:

$P(X < 6) = P(X < 4) + P(X = 5) = 0.5958 + P(X = 5)$

Negative probabilities do no exist, thus, this probability is guaranteed to be above 0.05, which means that it would not be unusual if fewer than half covered their mouth when sneezing.

A similar problem is given at brainly.com/question/24923631

3 0

2 years ago

Is this answer correct with all the variables including

Molodets [167]

13a - 2 is the answer, because 16(a-2) become 16 - 32, not 16a - 14.
:)
Brainliest Please

4 0

3 years ago

What is an algebraic expression to represent the perimeter of a rectangle with a width of x+5 and a length of 3x+10?

Sveta_85 [38]

We know that the area of a rectangle is equal to the width multiplied by the length. So in this case the algebraic expression is (x+5)*(3x+10). You get 3x^2 +10x +15x +50= 3x^2 +25x +50.

5 0

3 years ago

Answer these please tell me <br> 1. What the error was<br> 2. How can U check ur answer

emmainna [20.7K]

Answer:

The first one: the error was that the 3 shouldn’t have been moved but the 5 should have. The correct answer is k=-8

The second one: the error was that they added the 6 and 4, you would only get -10 if the 4 was - the correct answer is -2

You can check your answer by plugging in your answer to the variable and making sure both side equal each other

Step-by-step explanation:

The first one: the 5 should be - from both side so you get k=-8

The second one: the 4 should be + to both sides. And the -6 and +4 should be added together to get n=-2

Remember you always want to get the variables by themselves.

Sorry that was a lot. Hope it helps!

8 0

3 years ago

How do I solve this arithmetic sequence and find the next four terms?

ololo11 [35]

Answer:

252

Step-by-step explanation:

t50 = t1 + (n - 1)(d)

= 7 + (50 - 1) (5)

= 7 + (49)(5)

= 7 + 245

= 252

6 0

3 years ago

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