We are given the functions:
f(x) = 4 x – 5 --->
1
g(x) = 3 x + 7 --->
2
To find for the value of f(x) + g(x), all we have to do is
to add equations 1 and 2:
f(x) + g(x) = 4 x – 5 + 3 x + 7
f(x) + g(x) = 7 x + 2 = y
In this case, for any real number value assign to x, we get
a real number value of y. This is because the function is linear.
Therefore the domain of the function is all real numbers.
Answer:
18/4
Step-by-step explanation:
let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
DIFFERENTIATION
6+f(28+b(4)=6+112f+4bf
b=6+112f/-4f
b=1*6^0+1*112f^0/1*-4f^0
b=1+1/1
b=2