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3 years ago

Solve: 5/2x - 1/3= -1/2A. x=-5/12B. x= -25/12C. x= -1/15D. x= 1/3

Mathematics

2 answers:

devlian [24]3 years ago

7 0

Answer:

c. x = -1/15

Step-by-step explanation:

5/2x - 1/3 = -1/2 [multiply the whole equation by 6 (lowest common denom)

15x - 2 = -3 [add 2 on both sides of equation

15x = -1 [divide both sides by 15 to isolate x]

x = -1/15

pickupchik [31]3 years ago

5 0

Answer is c. Change the denominator of 1/3 and 1/2 to 6 so you have 3/6 for 1/2 and 2/6 for 1/3. then add 2/6 to both sides to get -1/6 then isolate x.

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Vilka [71]

Answer:

$m=-1$

Step-by-step explanation:

Start by multiplying both sides by 2, this will get rid of the fraction on the left side and will result in the equation $12m+6=2m-4$

Then, subtract 2m from both sides, which leaves the equation as $10m+6=-4$

Then, subtract 6 from both sides, this results with the equation $10m=-10$

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3 years ago

Directions : Factor each of the following Differences of two squares and write your answer together with solution

N76 [4]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Factor each of the following differences of two squares and write your answer together with solution.

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

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$\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}$

__________________

$\sf \: 49 - x ^ { 2 }$

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$\sf \: \left(7-x\right)\left(7+x\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}$

__________________

$\sf \: 81 - c ^ { 2 }$

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf\left(9-c\right)\left(9+c\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}$

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$\sf \: m ^ { 2 } n ^ { 2 } - 1$

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