The lot is <u>9.2% of the an acre.</u>
<u>Given:</u>
Area of an acre = 4840 sq. yards
Area of lot = 40 by 100 ft = ![40 ]\times 100 = 4,000 $ ft^{2}](https://tex.z-dn.net/?f=40%20%5D%5Ctimes%20100%20%3D%204%2C000%20%24%20ft%5E%7B2%7D)
Convert the area of the lot to feet (
):
<em>Therefore:</em>
Area of lot = 
Percentage occupied by the lot = area of lot / area of acre x 100
The lot therefore is <u>9.2% of the an acre</u>.
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I believe you do it like this:
1/2 Q+5/2
divide 1/2 into each term
to divide multiply by the reciprocal
1/2 x2/1= 1
5/2 x 2/1=5
1/2(Q+5)
2/sqrt 5
by rationalising the denominator,
2/sqrt 5 × sqrt 5/sqrt 5
= 2(sqrt 5)/sqrt 5(sqrt 5)
= 2 sqrt 5/5
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hope this helps! :))))
52s + 30b because 52 x s + 30 x b = 52s + 30b
X/8 = 19/13 => x = (8*19)/13 = 11.69 inches long;
