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horrorfan [7]
3 years ago
11

Solve the equation for x. -x^2+14=10

Mathematics
2 answers:
amid [387]3 years ago
7 0
-x^2= -4 then cancels the minus signs on both sides and square root the 4
x= 2
mariarad [96]3 years ago
4 0
-x^2 + 14 = 10

subtract 14 from each side

-x^2 = -4

divide each side by -1

x^2 =4

square root each side

x = 2

hope this helps!!! :)
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Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,
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Answer:

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Step-by-step explanation:

we know that                              

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)                      

Let                                          

a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5

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a_2-a_1=-7-(-10)=3              

a_3-a_2=-4-(-7)=3                  

a_4-a_3=-1-(-4)=3                        

a_5-a_4=2-(-1)=3                              

a_6-a_5=5-2=3                                                        

The difference between one term and the next is a constant        

This constant is the common difference                  

so                                                                                                                                  

The sequence graphed is an Arithmetic Sequence                    

therefore                                                                                    

The first term is a_1=-10                                    

The common difference is equal to d=3          

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