Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Answer:
first one, u can't ride a decimal of a ride
Step-by-step explanation:
y = 7.50 + 2.50x
First substitute the second equation into the first one:
-3x - 3(-5x - 17) = 3
Next distribute the parenthesis:
-3x + 15x + 51 = 3
Then combine like terms:
12x + 51 = 3
Now subtract 51 from each side:
12x = 48
Lastly to get x, divide each side by 12:
x = 4
Now put this into the second equation:
y = -5(4) - 17
Multiply:
y = -20 - 17
And subtract:
y = -37
The solution is (4,-37). Hope this helps!
(4a)2
Then when simplified it's-- 16a2
- Apply the product rule to 4
a
.
4
2
a
2
- Raise 4 to the power of 2.
16
a
2
<em>- Ouma</em>
I hope this helps you
x-3x= -4
-2x= -4
x=2
y= -3.2
y= -6
