A.)The equation is 24 + 8=32. Twice of the amount of 24 is 6 times the amount of 8. 24 x 2= 48. 48/6=8.
B.) X +Y=32 and 2x=6y
Answer: 0.01
Step-by-step explanation:
Let the events are :
C = paving stones found to be cracked.
D = paving stones found to be discolored.
Given : Total stones : T = 600 (i)
C = 15
D= 27
C'∩D'= 564 (ii)
Since C'∩D' = (C∪D)' = T- C∪D (iii)
From (i) , (ii)and (ii) , we have
564 = 600- C∪D
⇒ C∪D=600- 564= 36
Formula : C∩D= C+D- C∪D
Put values , we get
C∩D= 15+27-36=6
Now ,
The probability that it is both cracked and distorted is 0.01.
Anserr what the question?
Step-by-step explanation:
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
