Answer:
It's value is less than 0
Step-by-step explanation:
Answer:
1) f(g(0)) = 0
2) g(f(2)) = 2
3) g(g(0)) = 8
Step-by-step explanation:
Here, the given functions are:
g(x) = 3 x +2 and f(x)= (x-2)/3
1. Now, f(g(x)) = f(3x+2)
Also, f(3x+2) = (3x+2 -2) /3 = x
So, f(g(x)) = x
⇒ f(g(0)) = 0
2. g(f(x)) = g((x-2)/3) = 3((x-2)/3) +2
or, g(f(x)) = x
⇒ g(f(2)) = 3((2)-2/3) +2 = 2
or, g(f(2)) = 2
3. g(g(0)= g( 3 (0) +2) = g(2)
Now, g(2) = 3(2) + 2 = 6 + 2 = 8
or, g(g(0)) = 8
Answer:
c. 273 cars
Step-by-step explanation:
First you need to find what 16% of 325 is
325x.16=52
because the number sold dropped by 16% you will subtract 52 from 325
325-52=273
you can also calculate the answer by subtracting 100% by 16%
100%-16%=84%
now you can calculate 84% of 325
325x.84=273
Answer:
2.48×10^13 miles
Step-by-step explanation:
There are about (365.25 days)(86400 seconds/day) = 31,557,600 seconds in one year. There are 1609.344 meters in one mile. So, the conversion can be written as ...
(4.22 ly) (3×10^8 m/s) (3.15576×10^7 s/yr) / (1.609344×10^3 m/mi)
= 4.22×3×3.15576/1.609344×10^(8+7-3) mi
≈ 24.8×10^12 mi
4.22 light years is about 2.48×10^13 miles
The difference from distance and displacement is <u>the direction</u>
<h3>Further explanation</h3>
Distance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has magnitude
Can be simplified distance = total meters traveled
displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction
Can be simplified displacement = distanced traveled from starting point to ending point
Some examples of distanced and displacement
1. first move: move 4 meters north
second move: move 2 meters south
Distanced: 6 meters
Displacement: 2 meters north
2. first move: move 2 meters east
second move: move 4 meters west
Distanced: 6 meters
Displacement: 2 meters west
etc
<h3>Learn more</h3>
uniformly accelerated motion
brainly.com/question/13750982
Keywords: distance and displacement lab activity
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