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mixer [17]
3 years ago
15

Which function in the vertex form is equivalent to f(x)=4+x2-2x

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

f(x) = 4x - x² - 2x


Vertex form of a parabola: y = a(x - h)² + k where (h, k) is the vertex of this parabola


y = a.(x - h)² + k


y = -1.(x - h)² + k


Let's factor:


f(x) = -x² - 2x + 4

f(x) = -(x + 1)² + 1 + 4

f(x) = -(x + 1)² + 5


So we don't even need to find the vertex, we can just factor.

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jenyasd209 [6]

perimeter=2(85)+π(12.5)=220+2×12.5π

=170+25×3.14

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=248.5

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i hope this work for you

3 0
3 years ago
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kirill115 [55]
The answer is 4x that the answer
7 0
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Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.

Hope this Helps!!!

4 0
3 years ago
Verify that the given functions form a fundamental set of solutions of the differential equation on the indicated interval. Form
Zina [86]

Answer:

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Step-by-step explanation:

given,

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writing characteristics equation

m⁴ -1  =  0

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hence, roots of the equation comes out to be

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  y =C₁eˣ + C₂e⁻ˣ  + C₃ cos x + C₄ sin x

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I believe your answer should be 5!

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