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Lelechka [254]
3 years ago
13

A high school track is shaped as a rectangle with a half circle on either side. A rectangle has a length of 85 yards and width o

f 25 yards. 2 semicircles with diameters of 25 yards are on each end of the rectangle. Jasmine plans on running three laps. How many yards will Jasmine run? Use 3. 14 for Pi. 248. 5 yd 490. 5 yd 725. 5 yd 745. 5 yd.
Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

perimeter=2(85)+π(12.5)=220+2×12.5π

=170+25×3.14

=170+78.5

=248.5

distance ran=3×248.5=745.5 yards.

i hope this work for you

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Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

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