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Tems11 [23]
3 years ago
11

What is one difference between fixed–rate mortgages and variable–rate mortgages?

Mathematics
1 answer:
Illusion [34]3 years ago
6 0

Answer: The answer would be Variable- rate mortgages usually start at lower interest rates than fixed-rate mortgages.


Step-by-step explanation:

First of all let us know what fixed-rate mortgages and variable-rate mortgages are.


In fixed rate mortgages interest rates are fixed when we take loan and remain same for loan's entire term and it has nothing to do with market interest rate changes.


While in variable-rate mortgages interest rates may go up and down because it changes as market interest rate change.


Upon looking at our options we can see that option B is correct because usually variable-rate mortgages start at lower interest rates than fixed-rate mortgages and goes up or down according to market interest rate change.



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4 years ago
The probability is 0.4 that a traffic fatality involves an intoxicated or​ alcohol-impaired driver or nonoccupant. In 7 traffic​
Luden [163]

Answer:

a.

P(X=3)=0.2903\\\\P(X \geq  3)=0.5801\\\\P(X\leq 3)0.7102

b.

P(2\leq x\leq 4 )=0.7451

c. mean=2.8

d . standard deviation=1.2961

Step-by-step explanation:

We determine that the accident rates follow a binomial distribution. The rate of success p=0.4 and sample n=7:

P(x)={n\choose x}p^x(1-p)^{n-x}

#the probability of exactly​ three;

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X=3)={7\choose 3}0.4^3(0.6)^{4}\\\\=0.2903

#At least(more than 2)

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X\leq 2)\\\\=1-{7\choose 0}0.4^0(0.6)^{7}-{7\choose 1}0.4^1(0.6)^{6}-{7\choose 2}0.4^2(0.6)^{5}\\\\=1-0.0280-0.1306-0.2613\\\\=0.5801

#At most 3;

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X \leq 3)={7\choose 0}0.4^0(0.6)^{7}+{7\choose 1}0.4^1(0.6)^{6}+{7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}\\\\\\\=0.0280+0.1306+0.2613+0.2903\\\\=0.7102

b. Between 2 and 4:

Using the binomial expression, this probability is calculated as:

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(2\leq x\leq 4 )={7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}+{7\choose 4}0.4^4(0.6)^{3}\\\\\\\\\=0.2613+0.2903+0.1935\\\\=0.7451

Hence,the probability of between 2 and four is 0.7451

c. From a above, we have the values of n=7 and p=0.4.

-We substitute this values in the formula below to calculate the mean:

-The mean of a binomial distribution is calculated as the product of the probability of success by the sample size, mean=np:

\mu=np, n=7, p=0.4\\\\\mu=7\times 0.4\\\\=2.8

Hence, the standard deviation of the sample is 2.8

d. From a above, we have the values of n=7 and p=0.4

--We substitute this values in the formula below to calculate the standard deviation

-The standard deviation a binomial distribution is given as:

\sigma={\sqrt {np(1-p)}\\\\=\sqrt{7\times 0.4\times 0.6}\\\\=1.2961

Hence, the standard deviation of the sample is 1.2961

4 0
3 years ago
My number A is 24.
slavikrds [6]

Answer:

24

Step-by-step explanation:

LCM=24

HCF=24

Therefore B=24

4 0
3 years ago
Read 2 more answers
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