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2 years ago

What is one difference between fixed–rate mortgages and variable–rate mortgages?

1 answer:

6 0

Answer: The answer would be Variable- rate mortgages usually start at lower interest rates than fixed-rate mortgages.

Step-by-step explanation:

First of all let us know what fixed-rate mortgages and variable-rate mortgages are.

In fixed rate mortgages interest rates are fixed when we take loan and remain same for loan's entire term and it has nothing to do with market interest rate changes.

While in variable-rate mortgages interest rates may go up and down because it changes as market interest rate change.

Upon looking at our options we can see that option B is correct because usually variable-rate mortgages start at lower interest rates than fixed-rate mortgages and goes up or down according to market interest rate change.

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Can someone help me with at least one problem and tell me how you got the answer

Vesna [10]

S=16t^2
if t=3
So you would plug it in
16(3)^2
Then you multipy
16*3^2
=144
It is easier if you use a calculator just type in ti 30 calculator online that should help

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3 years ago

What are the zeros of f(x) = (x − 5)(x − 4)(x − 2)?

Dominik [7]

Answer:

x=5 , x=4, x=2

i got this answer by setting the x-5=0 then solve for x. same for each x-5, x-4, x-2.

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2 years ago

Read 2 more answers

Graphing linear equations y+5=-2(x-2)

levacccp [35]

First put the equation in y=mx+b form then plot the b and count off the slope.

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3 years ago

Bodhi has a collection of 175 dimes and nickels. The collection is worth $13.30. Which equation can be used to find n, the numbe

Stels [109]

X = Dimes Y = Nickels
x + y = 175
.10x + .05y = 13.30

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3 years ago

What is number 61 and a step by step explaination please?

astra-53 [7]

1/3 ln(x) + ln(2) - ln(3) = 3

Recall that $m\log_b(n)=\log_b(n^m)$ , so

ln(x ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

$\log_b(m)+\log_b(n)=\log_b(mn)$

$\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)$

Then

ln(2/3 x ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant e. (I'm using exp(x) = e ˣ so I can write it all in one line.)

exp(ln(2/3 x ¹ʹ³)) = exp(3)

Now exp(ln(x)) = x for all x, so this simplifies to

2/3 x ¹ʹ³ = exp(3)

Now solve for x. Multiply both sides by 3/2 :

3/2 × 2/3 x ¹ʹ³ = 3/2 exp(3)

x ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(x ¹ʹ³)³ = (3/2 exp(3))³

x = 3³/2³ exp(3×3)

x = 27/8 exp(9)

which is the same as

x = 27/8 e ⁹

3 0

3 years ago