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bulgar [2K]
3 years ago
6

A major car manufacturer wants to test a new engine to determine if it meets new air pollution standards. The mean emission, μ,

of all engines of this type must be approximately 20 parts per million of carbon. If it is higher than that, they will have to redesign parts of the engine. Ten engines are manufactured for testing purposes and the emission level of each is determined. Based on data collected over the years from a variety of engines, it seems reasonable to assume that emission levels are roughly Normally distributed with σ = 3 parts per million of carbon. What are the appropriate null and alternative hypotheses?
Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

Answer:

Step-by-step explanation:

the appropriate null and alternative hypotheses's are something

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1 pound -> 143/132

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3 years ago
What is the answer? Plz help
Veronika [31]

Answer:

D and C

Step-by-step explanation:

You just write the numbers and see how many zeroes they have

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Please help
poizon [28]

Answer:

D

Step-by-step explanation:

4 people = 15 days

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= 22.5

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3 years ago
Helpppp big brains am I right??
noname [10]

Answer:

y=3x+4

Step-by-step explanation:

This is the correct answer

7 0
2 years ago
A group of 30 students from your school is part of the audience for a TV game show. The total number of people in the audience i
s344n2d4d5 [400]

Answer:

5.3%

Step-by-step explanation:

The final probability is calculated by means of the quotient of the specific combinations and the total of total combinations

Let's start with the specific ones,

First the number of combinations of 4 of the 30 students getting a spot, i.e .:

A combinations are equal to:

nCx = n! / x! * (n-x)!

Replacing:

30C4 = 30! / (4! * 26!) = 27405

Segundo the number of combinations of the other audience members filling the other 4 (8-4) spots n = 110, 140 - 30

110C4 = 110! / (4! * 106!) = 5773185

Now the total combinations of possible 8 contestants from the audience

140C8 = 140! / (8! * 132!) = 2.98 * 10 ^ 12

Finally, the probability is equal to:

P = (30C4 * 110C4) / 140C8

replacing:

P = 27405 * 5773185 / 2.98 * 10 ^ 12

P = 0.053

Therefore the probability is 5.3%

4 0
3 years ago
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