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Fynjy0 [20]
3 years ago
10

Plz help me!!!!!!!!!

Mathematics
1 answer:
Over [174]3 years ago
7 0

Answer:  \bold{\dfrac{4\pm \sqrt{6}}{2}}

<u>Step-by-step explanation:</u>

\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}

.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}

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HELP ASAP PLEASE &amp; SHOW UR WORK!! THANK YOU &lt;333
alekssr [168]

Answer:

              \bold{x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\quad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7}

Step-by-step explanation:

-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7

4 0
3 years ago
Evaluate the expression!
Fudgin [204]

Answer:

poop

Step-by-step explanation:

5 0
3 years ago
what positive number satisfies the condition that twice the number minus three times the reciprocal of the number is equal to 1?
marshall27 [118]
Solve:

"<span>twice the number minus three times the reciprocal of the number is equal to 1."
                                                     3(1)
Let the number be n.  Then 2n - ------- = 1
                                                       n

Mult all 3 terms by n to elim. the fractions:

2n^2 - 3 = n.  Rearranging this, we get 2n^2 - n - 3 = 0.

We need to find the roots (zeros or solutions) of this quadratic equation.

Here a=2, b= -1 and c= -3.  Let's find the discriminant b^2-4ac first:

disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.

That's good, because 25 is a perfect square.
                -(-1) plus or minus 5         1 plus or minus 5
Then x = ------------------------------ = --------------------------
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x could be 6/4 = 3/2, or -5/4.

You must check both answers in the original equation.  If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
8 0
3 years ago
Two numbers are missing from this table. How can the missing numbers be
KiRa [710]

Answer:

multiply input number by 4

Step-by-step explanation:

In the figure attached, the problem is shown.

We can see the following values:

input = 1, output = 4*1 = 4

input = 4, output = 4*4 = 16

input = 7, output = 4*7 = 28

Then, the missing numbers can be found multiply input number by 4

3 0
3 years ago
In the figure below what is the name of the angle formed by two rays QR and QP? What is the common. endpoint,for this angle?
castortr0y [4]
The common endpoint is Q. The angle is: angle RQP, angle PQR, or just angle Q
6 0
3 years ago
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