All categories

3 years ago

PLEASE HELP QUICK!

English

2 answers:

Makovka662 [10]3 years ago

6 0

Answer:

C) She wants to share in her daughter’s accomplishments.

Explanation:

The narrator's mother is proud of her accomplishments as a chess player. Waverly has won many tournaments and has many accolades. Her mother is willing to do whatever is needed in order to make sure that Waverly can continue to be successful at chess. Waverly's mother wants to share in her daughter's accomplishments by showing her off in their community. Eventually Waverly tires of this and yells at her mother.

egoroff_w [7]3 years ago

3 0

i believe the answer is C

You might be interested in

Read the sentence. Lisa saddles the horse. What is the direct object

Mazyrski [523]

The horse is the direct object

4 0

3 years ago

Select all the correct answers.

sergejj [24]

Answer:

Precautions must be taken by motorists if food is consumed while driving.

Explanation:

8 0

3 years ago

select the prepositional phrase 1. although it seems healthy 2. despite the efforts 3. the number of visitors 4. with an increas

Nikitich [7]

Answer:

4. with an increasing number

Explanation:

A prepositional phrase is a modifying phrase consisting of a preposition and its object.

6 0

3 years ago

Read 2 more answers

The Hanseatic League was the name for a group of ________ towns who worked to encourage trade in their regions. English Italian

aivan3 [116]

It is German towns :)

7 0

3 years ago

Read 2 more answers

I will make you brainlist if you help me the 2 question by explain them i swear i will make you brainlist

Xelga [282]

★ Formula Applied :

$\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}$

$\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}$

$\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}$

$\bullet\ \; \sf \ln (ab)=\ln a+\ln$

★ Explanation :

$\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}$

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

$\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}$

$\to \sf \red{-ln|sin2x|+c}$

$\to \sf - \ln |2sinx.cosx|+c$

$\to \sf - \ln |sinx.cosx|+(\ln 2+c)$

$\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar$

★ Alternate Method :

$\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}$

$\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx$

$\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}$

$\to \sf ln\left| \dfrac{secx}{sinx}\right|+c$

$\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}$ ]

$\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar$

4 0

3 years ago