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3 years ago

3x-4>x+8 as a sentence

Mathematics

2 answers:

Mumz [18]3 years ago

6 0

Three x minus four is greater than x plus 8

bixtya [17]3 years ago

5 0

Answer: Three x minus 4 is greater than x plus 8.

Explanation: All that you have to do it write what you see.

3 = three

x = x

- = minus

4 = four

> = greater than

x = x

+ = plus

8 = eight

Hope this helps! :)

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For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

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4 years ago

Jerome works as a waiter he earns $80 each weekend plus 15% in tips

valentina_108 [34]

15% of 80 is 12, so he got $12 in tips
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sp2606 [1]

Answer:

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Step-by-step explanation:

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4 1/4 = 4 2/8

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Blizzard [7]

(x+4)+v<=14 is the equation
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What type of quadrilateral has to the vertices A(3,6), B(3,3), C(6,3), and D(6,6)

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