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3 years ago

Suppose x is any positive number why is circle 1 similar to circle

Mathematics

1 answer:

Nostrana [21]3 years ago

3 0

Answer:

A circle 2 is a dilation of circle 1 with a scale factor of 5

Step-by-step explanation:

We have been given information about two circles as given below:

circle 1: center (0,0) and radius 2x

circle 2: center (0,0) and radius 10x .

Now we need to find about why is circle 1 similar to circle where x is any positive number.

We know that all circles are similar. So after dilation it doesn't affect their similarities.

10x can be obtained from 2x, by multiplying 2x with 5.

So the first choice "A circle 2 is a dilation of circle 1 with a scale factor of 5" is correct.

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3 years ago

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3 years ago

Write the equation for Chelsea's graph in

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Answer:

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6 0

3 years ago

Ignore circled one and work it out please

mash [69]

Answer:

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$

3 0

3 years ago