Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
Answer:
DE = 18
Step-by-step explanation:
Given that,
Point D is on line segment CE.
DE = x+10, CD=6 and CE=3x
We need to find the length of DE.
ATQ,
CE = CD + DE
Putting all the values,
3x = 6 + x+10
Taking like terms together
3x-x = 16
2x = 16
x = 8
DE = x+10
= 8+10
= 18
Hence, the length of DE is 18.
Im not that good with these types of problems but i think it is b if my math is correct.
The correct answer is: [B]: " y = 9 " .
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Answer:
36
Step-by-step explanation:
18 × 2 = 36
Because 1/2 is half of 1 kg so multiply by 2 it makes 1 kg
