440 thousands. You take out the three zeros and you'll get your answer. Hope it helps! :)
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
Answer:
A.
Step-by-step explanation:
38% = 38/100 = 0.38
A percentage is anything over 100
Answer:
x>3
Step-by-step explanation:
8x-6>12+2x
Subtract 2x from both sides:
6x-6>12
Add 6 to both sides:
6x>18
Divide both sides by 6:
x>3
Hope this helps!