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Lera25 [3.4K]
3 years ago
5

What value of X is in the solution set of 8x - 6 > 12 + 2x

Mathematics
2 answers:
marin [14]3 years ago
5 0

Answer:

x>3

Step-by-step explanation:

8x-6>12+2x

First start distributing your numbers

the 2x will go to the left and turn to -2x and the -6 will go to the right and turn to +6

Then you will get the answer of 6x > 18

Now you will need to get the x by itself, so divide the 6 by the 18 on the right and you will get the answer.

Molodets [167]3 years ago
3 0

Answer:

x>3

Step-by-step explanation:

8x-6>12+2x

Subtract 2x from both sides:

6x-6>12

Add 6 to both sides:

6x>18

Divide both sides by 6:

x>3

Hope this helps!

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Simplify expression x8y-26/x14y-5 × x-39y-21
koban [17]

The simplified form of the expression is x^{-45} y^{-42}

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

The expression can be simplified as shown below

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

\frac{x^{8} \times x^{-39} \times  y^{-26} \times  y^{-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8+-39} \times  y^{-26+-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8-39} \times  y^{-26-21}  }{x^{14} \times y^{-5}  }

\frac{x^{-31} \times  y^{-47}  }{x^{14} \times y^{-5}  }

Then,

\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }

x^{-31-14} \times y^{-47--5}

x^{-31-14} \times y^{-47+5}

x^{-45} \times y^{-42}

x^{-45} y^{-42}

Hence, the simplified form of the expression is x^{-45} y^{-42}

Learn more on Simplifying an expression here: brainly.com/question/2320607

#SPJ1

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