Answer:
The limit that 97.5% of the data points will be above is $912.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the limit that 97.5% of the data points will be above.
This is the value of X when Z has a pvalue of 1-0.975 = 0.025. So it is X when Z = -1.96.
So




The limit that 97.5% of the data points will be above is $912.
Kx=y-m
x=(y-m)/k
Note that this is also standard linear form, x=y/k-m/k where slope=1/k and x intercept is -m/k.
Answer:
YES, HAVE A GREAT DAYYYYYYYYYYYY!!!
Step-by-step explanation:
THX 4 THE POINTS!!!!!
Real world example could be:
Consider x is time in minutes
Consider y is the amount of fish food required in grams
The equation could then represent how much food (in grams) that a fish needs to be fed x minutes after it was previously fed.
V = a * b * c
V = 30
a = 5
b = 2
c = ?
30 = 5*2*c
30 = 10*c
c = 30/10 = 3
c = 3