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pochemuha
2 years ago
7

Compare the graph of g(x) = x^2 + 6 with the graph of f(x)=x^2

Mathematics
1 answer:
Verdich [7]2 years ago
6 0

If the parent graph is transformed to x^2 + 6, this shows that the parent function translated 6 units up the graph to create the graph x^2+6

<h3>What are quadratic graphs</h3>

These are graph with function of leading degree of 2. The parent function for a quadratic graph is x^2

f(x)= x^2

If the parent graph is transformed to x^2 + 6, this shows that the parent function translated 6 units up the graph to create the graph x^2+6

Learn more on translation here; brainly.com/question/12861087

#SPJ1

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Plz help I have to do a test tomorrow on this!
melomori [17]

What do you need help with? Nothing is showing :/

4 0
3 years ago
The City Transit Authority plans to hire 12 new bus drivers. From a group of 100 qualified applicants, of whom 65 are men and 35
QveST [7]

Answer:

1. About 1/5 chance that Mary is chosen

About 1/7 chance John is chosen

2. about 0.0286 chance mary is chosen

about  0.0154 chance john is chosen

same as answer 2

Step-by-step explanation:

1.  If you do proportions, a female's chance comes to 1/5 and a male's chance comes to 1/7.

2. for females, do 1/35  and males do 1/65

same as answer 2

4 0
3 years ago
Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!! I don't understand it!
katrin2010 [14]

Answer:

  13.98 in²

Step-by-step explanation:

I don't understand it, either.

Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.

__

The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.

The area of a segment is given by the formula ...

  A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.

Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...

  A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²

Rounded to hundredths, this is ...

  ≈ 13.98 in²

3 0
3 years ago
Explain and solve .<br>hhhhgghgfghhg​
Aleks [24]

Answer:

mark as brainliest and drop some thanks!!!

5 0
3 years ago
Find the coordinates for the midpoint of the segment with endpoints give (3,5) and (-2,0)
Leto [7]

Answer:

The coordinates of the mid-point are :

(\frac{1}{2}, \frac{5}{2})

Step-by-step explanation:

We know that, the coordinates of the mid-point (<em>x</em>, <em>y</em>) of a line segment joining the points (<em>x</em>₁, <em>y</em>₁) and (<em>x</em>₂, <em>y</em>₂) is given by

(x, y) = (\frac{x_{1} +x_{2} }{2},\frac{y_{1}+y_{2} }{2} )

Now, we have the given points as (3, 5) and (-2, 0).

By using the above formula, coordinates of the mid-point (<em>x</em>, <em>y</em>) of the line-segment joining the points (3, 5) and (-2, 0) is given by,

x = \frac{3+(-2)}{2} = \frac{3-2}{2} = \frac{1}{2}

y = \frac{5+0}{2} = \frac{5}{2}

∴ coordinates of the mid-point of the line-segment joining the points (3,5) and (-2,0) is (\frac{1}{2}, \frac{5}{2}).

8 0
3 years ago
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