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ryzh [129]
3 years ago
6

Evaluate the following expression 6 - 2 x 1

Mathematics
1 answer:
torisob [31]3 years ago
3 0
6 - 2 x 1

= 6 - 2

= 4



We have to use the PEDMAS method in solving all kinds of calculation expression.

P = Parentheses (or brackets)
E = Exponents (or Index)
D = Division
M = Multiplication
A = Addition
S = Subtraction
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Truck driver drives for five hours at a constant speed of 55 mph. Write an equation that shows the total distance traveled (y) d
wel

Step-by-step explanation:

y = 55x \\ because \\ distance \ = :  \: speed \: \times   \: time

plzzz.. .......

mark it as a brilliant answer

3 0
3 years ago
A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha
ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                          P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students received a passing grade = 77%

           n = sample of tests = 40

           p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                           level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

 = [ 0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } , 0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } ]

 = [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0
3 years ago
Se compra un auto nuevo por 17900 dólares.El valor del automóvil se deprecia en 12.25% por año.¿cual será el valor del automóvil
jeyben [28]

17,900 x 0.1296 = 2318.05

2318.05 should be subtracted from 17,900 and it should be somewhere around 15,581.95

4 0
3 years ago
Find the probability of the event. The probability of not choosing a black shirt.
Nata [24]

Answer:

10 of 1

Step-by-step explanation:

just think about it

8 0
3 years ago
How to expand and simplify 5(3p+2)-2(5p-3)
Luda [366]
5(3p+2) - 2(5p-3)     Distribute the 5 and the 2
(5*3p) + (5*10) + (-2*5p) + (-2*-3)
15p + 50 - 10p + 6      Combine like terms
5p + 56
5 0
3 years ago
Read 2 more answers
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