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anzhelika [568]

3 years ago

15

ted drove his new car for 260 miles. the trip took 4 and a half hours, he used 6 gallons of fuel, which cost $2 per gallon. how

much did he spend on the fuel?

2 answers:

neonofarm [45]3 years ago

8 0

He used 12 dollars in gasoline.

andrey2020 [161]3 years ago

3 0

He spent $12 on fuel

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Select the correct answer. which expression is equivalent to the given expression? assume the denominator does not equal zero. a

Alexxandr [17]

If the denominator does not equal 0, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$ $\frac{x^{10} y^{14}}{729}$

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

$\frac{14x^4y^6}{7x^8y^2}$

Divide 14 by 7

$\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}$

Apply the law of indices

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}$

Evaluate the differences in the exponents

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{4}}{x^{4}}$

Hence, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$

Read more about equivalent expressions at:

brainly.com/question/2972832

#SPJ4

4 0

2 years ago

Alisa had 1 & 1/2 liter of juice in a bottle. She drank three eighths liters of juice. What fraction of the juice in the bot

emmasim [6.3K]

Answer:

1/4

Step-by-step explanation:

The fraction of the juice Alisa drank was

3/8 liter

--------------------

3/2 liters

and this fraction can be simplified by inverting the divisor (3/2 liters) and multiplying instead:

3 2

------ * ----- = 2/8 or 1/4

8 3

Alisa drank 1/4 of the juice that was originally in the bottle.

4 0

3 years ago

Read 2 more answers

Iodine-125 has a daily decay rate of about 1%. How many milligrams of a 500 mg sample will remain after 300 days? Round the answ

Amanda [17]

So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400

$\bf \qquad \textit{Amount for Exponential change}\\\\
A=P(1\pm r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{starting amount}\to &500\\
r=rate\to 1\%\to \frac{1}{100}\to &0.01\\
t=\textit{elapsed period}\to &300\\
\end{cases}
\\\\\\
A=500(1-0.01)^{300}$

7 0

3 years ago

Read 2 more answers

Complete the tables to determine if the expressions are equivalent. If the expressions are equivalent, name the properties that

jok3333 [9.3K]

I don’t know how to necessarily complete the tables but i know they are equivalent

1. 3(x-5)
3 (x) = 3x
3 (-5) = -15

that is the distributive property thus it equals

3x - 15

2. 3x - 15

they’re the same

5 0

2 years ago

A) .2<br> B).25<br> C).35<br> D).4

Lesechka [4]

Answer:

2 the answer cause 2×2=4

7 0

3 years ago