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timofeeve [1]
4 years ago
15

Need help PLEASE (photo attached)

Mathematics
2 answers:
ivolga24 [154]4 years ago
8 0
Yermi, because the square root of .50 is 0.7071067812. This is the best approximation of the square root of .50
Svetllana [295]4 years ago
5 0
Third one hope this helped

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Write any two quadratic equations​.
Thepotemich [5.8K]

To find:

Any two quadratic equations​.

Solution:

The general form of a quadratic equation is:

ax^2+bx+c=0

Where, a,b and c are real number and a is non zero.

We know that a,b,c can take any values but a cannot be 0.

For a=1, b=1,c=1, we get

1x^2+1x+1=0

x^2+x+1=0

One quadratic equation is x^2+x+1=0.

For a=3,b=-1,c=5, we get

3x^2+(-1)x+5=0

3x^2-x+5=0

Therefore, the two quadratic equations are x^2+x+1=0 and 3x^2-x+5=0.

3 0
3 years ago
Reduce the ratio of 70 and 50
dem82 [27]

Answer:

7:5

Step-by-step explanation:

70 and 50 can be divided by 10

hope this helps you :)

4 0
3 years ago
Read 2 more answers
write an equation to represent the relationship, and find the amount of peanut butter used to make 25 cracker packages. the tabl
Nadusha1986 [10]

We are given 4 points.

(\frac{1}{2},2)

(\frac{5}{8},\frac{5}{2})

(\frac{3}{4},3)

(\frac{7}{8},\frac{7}{2})

Using this, we can make an equation.

y=4x

I got m=4 by using the slope formula.

m=\frac{2.5-2}{0.625-0.5}

m=\frac{0.5}{0.125}

m=4

So the equation we have is y=4x

Now, we can solve for how much peanut butter is used to make 25 packages by plugging in 25 for y, which is the number of cracker packages.

25=4x

x=\frac{25}{4}

We need to use \frac{25}{4} teaspoons of peanut butter to make 25 packages of crackers.

Hope this helps.

頑張って!

4 0
4 years ago
The Chicago Cubs have played in 28 less than twice the number of World Series Champion Than the St. Louis Cardinals. The cubs pl
aev [14]
The answer to your question is 11 world championships
8 0
3 years ago
Which of these statements is true for f(x)=5x(6)^x
bonufazy [111]

Answer:

The answer if B. Hope this helps.

Step-by-step explanation:

3 0
3 years ago
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