After he withdraws $50.00 in cash the bank reconciliation shows that Ryan would have: $1 501.98 in bank balance.
<h3>What is the solution to the above?</h3>
Add all the deposits
- 28 x 10 = 280
- 9 x 5 = 45
- 20 x 0.25 = 5
- 85 x 0.10 = 8.5
- 32 x 0.01 = 0.32
Total = $338.82
Add the checks
654.24 + 100.00 + 458.92
= $1,213.16
Total amount deposited is: Cash + Check
1,213.16 + 338.82
Total Deposit = $1,551.98
Less withdrawal of $50
$1,551.98 - $50
Balance left = 1 501.98
Learn more about Bank Transactions at;
brainly.com/question/15525383
#SPJ1
Full Question:
Ryan Massey wants to deposit the following into his savings account: 28 ten-dollar bills, 9 five-dollar bills, 20 quarters, 85 dimes, 32 pennies, and three checks for $654.24, $100.00, and $458.92. He wants to receive $50.00 in cash.
How much cash would he lave left after he withdraws $50.00 in cash?
Answer:
(A) 49
Explanation:
Given that the fractions are in their simplest form. So below the denominator cannot be a multiple of 3, 4, 5.
Breakdown:
Looking at option A (49), it is not a multiple of 3, 4, 5. So k can be 49.
Option B (50) is a multiple of 5. An even number like 4 so can be simplified.
Option C (51) is a multiple of 3 so can be simplified more. 3/51 = 1/17.
Option D (52) is an even number like 4 so can be simplified. 4/52 = 1/13.
Answer:
The answer is below
Step-by-step explanation:
Let a complex z = r(cos θ + isinθ), the nth root of the complex number is given as:
Given the complex number z = 81(cos(3π/8)+isin(3π/8)), the fourth root (i.e n = 4) is given as follows:
![z_{k=0}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(0)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(0)\pi}{4} ))=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})] \\z_{k=0}=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})]\\\\z_{k=1}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(1)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(1)\pi}{4} ))=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})] \\z_{k=1}=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})]\\\\](https://tex.z-dn.net/?f=z_%7Bk%3D0%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%280%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%280%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D0%7D%3D3%5Bcos%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%29%5D%5C%5C%5C%5Cz_%7Bk%3D1%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%281%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%281%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D1%7D%3D3%5Bcos%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%29%5D%5C%5C%5C%5C)
![z_{k=2}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(2)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(2)\pi}{4} ))=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})] \\z_{k=2}=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})]\\\\z_{k=3}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(3)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(3)\pi}{4} ))=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})] \\z_{k=3}=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})]](https://tex.z-dn.net/?f=z_%7Bk%3D2%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%282%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%282%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D2%7D%3D3%5Bcos%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%29%5D%5C%5C%5C%5Cz_%7Bk%3D3%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%283%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%283%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D3%7D%3D3%5Bcos%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%29%5D)
I assume you're looking for the sum.
I would use the null property to eliminate 0
34+0+18+26
=34+18+26
then use commutativity to rearrange
=34+26 + 18
Add 34+26=60
=60+18
=78
The answer i got is VP<------------->
AKA the first option
i hope this is right
