Problem referred below pls help
1 answer:
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Part A:
Derrick is incorrect.
A yard is equivalent to 3 feet.
Thus, 20 yards will be equivalent to 60 feet.
The width is 20 yard and 2 feet. It's the same as 60 feet and 2 feet, or 62 feet. Thus, Derrick is incorrect.
Part B:
Let's calculate the area of the parking lot.
We know the width is 62 feet from part A.
The length is 30 yards, or 90 feet.
Multiply the length and width to get the area in square feet.
The parking lot has an area of 5580 square foot.
It costs 2 dollars per square foot to repave the parking lot. Multiply the area by 2 dollars.
It will cost $11,160 to repave the whole parking lot.
Derrick is incorrect.
A yard is equivalent to 3 feet.
Thus, 20 yards will be equivalent to 60 feet.
The width is 20 yard and 2 feet. It's the same as 60 feet and 2 feet, or 62 feet. Thus, Derrick is incorrect.
Part B:
Let's calculate the area of the parking lot.
We know the width is 62 feet from part A.
The length is 30 yards, or 90 feet.
Multiply the length and width to get the area in square feet.
The parking lot has an area of 5580 square foot.
It costs 2 dollars per square foot to repave the parking lot. Multiply the area by 2 dollars.
It will cost $11,160 to repave the whole parking lot.
Answer:
Total weight of the wheat placed on 45th square will be =
Step-by-step explanation:
King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.
In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.
We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)
In a geometric progression we know the nth term =
where a = first term of the series, r = common ratio, n = number of terms
Now we have to calculate the weight of all wheat placed on 45th square.
So we will put the values in the given formula 45th term =
=
=
Then the weight of wheat will be = =