Answer:
forms because
is always a more stable species than the calcium atom alone
Explanation:
An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.Thus the electronegativity difference between the bonding atoms of ionic compounds is large.
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
In
, calcium is having an oxidation state of +2 called as
cation and chloride
is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral
.
Electronic configuration of calcium:
calcium atom will loose two electrons to gain noble gas configuration and form calcium cation with +2 charge.
Electronic configuration of chlorine
Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.
![[Cl^-]=1s^22s^22p^63s^23p^6](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D1s%5E22s%5E22p%5E63s%5E23p%5E6)
Ionic compounds with ionic bonds tend to have high melting points due to strong coulombic forces between them.
Answer: A. 4 unpaired electrons
B. Zero unpaired electrons
C. 1 unpaired electron
D. 5 unpaired electrons
E. Zero unpaired electrons
Explanation:
In A, Oxidation state of Co is +3 and Electronic configuration is [Ar]3d6
F is weak field ligand, causes no pairing of Electrons hence it has 4 unpaired electrons&2 are paired in t2g orbitals (dXY)
In B , Mn is in +3 with electronic configuration 3d4&CN is a strong field ligand hence causes pairing of Electrons hence it results 0 unpaired electron
In C, Mn is in +2 with electronic configuration 3d5 sinceCN is a strong field ligand hence it leaves one unpaired electron
In D, Mn is in+2 with 3d5& five unpaired electrons since cl is a weak field ligand causes no pairing.
In E, Rh is in +3, with d6 configuration and it is a low spin complex hence pairing of Electrons involved. So it leaves zero unpaired electrons.
Answer:
is a chemical bond i think is true
Answer:
ok, maybe draw like a few plants and dear, you know and draw them out of cells, like the shape. so like a bunch of cells together making the shape of a deer or plant and stuff. i hope this helps
Explanation: