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luda_lava [24]
4 years ago
7

Which of the following statements are true concerning ionic bonding? Select one: a. Ionic bonding occurs between a metal, which

has a high affinity for electrons, and a nonmetal, which loses electrons relatively easy. b. CaCl2 forms because Ca2+ is always a more stable species than the calcium atom alone. c. Compounds with ionic bonds tend to have low melting points. d. The electronegativity difference between the bonding atoms of ionic compounds is small since the electrons are not shared but rather held together by electrostatic forces. e. All of the above statements are false.
Chemistry
1 answer:
spin [16.1K]4 years ago
6 0

Answer: CaCl_2 forms because Ca^{2+} is always a more stable species than the calcium atom alone

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.Thus the electronegativity difference between the bonding atoms of ionic compounds is large.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

In CaCl_2 , calcium is having an oxidation state of +2 called as Ca^{2+} cation and chloride Cl^{-} is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral CaCl_2.

Electronic configuration of calcium:

[Ca]=1s^22s^22p^63s^23p^64s^2

calcium atom will loose two electrons to gain noble gas configuration and form calcium cation with +2 charge.

[Ca^{2+}]=1s^22s^22p^63s^23p^6

Electronic configuration of chlorine

[Cl]=1s^22s^22p^63s^23p^5

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

[Cl^-]=1s^22s^22p^63s^23p^6

Ionic compounds with ionic bonds tend to have high melting points due to strong coulombic forces between them.

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At 25°C 12 M H202 is decomposed after 30 minutes the concentration of the H2O2 is found to be 9.5 M what is the average reaction
Bess [88]
The decomposition reaction of hydrogen peroxide:
2 H₂O₂(aq) →  2 H₂O(l) + O₂(g)
The order of reaction is : first order reaction.
[H₂O₂]₀ = 12 M at time = 0
[H₂O₂] = 9.5 M at time = 30 minutes
Average reaction rate = - (Δ[reactants] / Δt) 
                   = - (final reactants conc. - initial reactants conc.) / Δt
                   = - (9.5 M -12 M) / (30 min - 0 min) 
                   = 0.083 mol / L.min
8 0
3 years ago
I need 2 examples of chemical and physical change. *15 points
melamori03 [73]
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3 0
3 years ago
Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p
Butoxors [25]

Answer:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

BiO_3^-\rightarrow Bi^{3+}

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

(Bi^{5+}O_3)^-\rightarrow Bi^{3+}

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Then, we accommodate the waters to obtain:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Best regards!

7 0
3 years ago
How much heat is released when 27.6 g P C l subscript 3 cools from 83.1 °C to 55.6 °C? (The specific heat of P C l subscript 3 i
Paul [167]

Answer: Thus 663 J of heat  is released when 27.6 g PCl_3 cools from 83.1 °C to 55.6 °C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat released = ?

m = mass of substance = 27.6 g

C = specific heat capacity = 0.874J/g^0C

Initial temperature= T_i = 83.1^0C

Final temperature  = T_f  = 55.6^0c

Change in temperature ,\Delta T=T_f-T_i=(55.6-83.1)^0C=-27.5^0C

Putting in the values, we get:

Q=27.6g\times 0.874J/g^0C\times -27.5^0C=-663J

As the value of q is negative, it means the heat has been released and it is 663J

7 0
3 years ago
What happens if you add a neutron to an atom?
Paladinen [302]

Answer:

if you add or subtract a neutron from an atom it will become a new isotopes of the same element

7 0
3 years ago
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