Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be 
.
The partial pressure of gas A can be written as 
= 
×P (where is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is = 
and 
respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be .
Which is different from the initial state.
I think the answer is OPC
Answer:
ecosystem:a biological community of interacting organisms and their physical environment.
rainforest: a luxuriant, dense forest rich in biodiversity, found typically in tropical areas with consistently heavy rainfall.
major part of rain forest:Most rainforests are structured in four layers: emergent, canopy, understory, and forest floor. Each layer has unique characteristics based on differing levels of water, sunlight, and air circulation.
coral reefs :a ridge of rock in the sea formed by the growth and deposit of coral.
type of coral reefs:fringing reefs, barrier reefs, atolls, and patch reefs
Explanation:
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Answer:
The answer to your question is 71.22 g
Explanation:
Data
Density = 19.3 g/cm³
Volume = 0.00369
mass = ?
Formula
Density = 
Solve for mass
mass = density x volume
Process
1.- Convert volume from liters to cubic centimeters
1 l ---------------- 1000 cm³
0.00369l --------- x
x = (0.00369 x 1000 ) / 1
x = 3.69 cm³
2.- Substitution
mass = 19.3 x 3.69
3.- Simplification and result
mass = 71.22 g
Answer:
Mass= volume x density
Explanation:
Multiply the density by the volume.
