3 years ago

Please answer A and B and give an explanation and show work. thank you!

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

4 0

Dont know a but b is
75=100-2p
75 minus 100 = -25=-2p
-25/-2= p
p=$12.50

You might be interested in

A graph that has a finite or limited number of data points is

Mandarinka [93]

a discrete graph (I had to look this one up)

4 0

2 years ago

A taxi driver determines the fare using the formula F=1.50+2.6m, where F is the total fare and m id the numbet a miles driven. W

Lady bird [3.3K]

Just do 1.50 + 2.6(3.5)

The answer is $10.60

3 0

3 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

8 0

3 years ago

What is this answer?????

aleksklad [387]

$50+x \leq 50$

Subtract 50 from both sides:

$50+x-50 \leq 50 - 50$

$x \leq 0$

hope this helps!

5 0

3 years ago

Simplify the expression.<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B%5Csqrt%7B3%7D-2%20%7D" id="TexFormula1" tit

zhannawk [14.2K]

Answer:

I have attached the work to your problem.

Please see the attachment below.

I hope this helps!

7 0

3 years ago