Using point slope form determine the equation of a line that is perpendicular to the line y=3x+4 and passes through point (6,-3)

1 answer:

8 0

I'm not gonna use point-slope form but I will tell you the equation in slope-intersect form. Perpendicular means that the slopes of the 2 equations have to be opposite reciprocals. That means if one is 2, the other slope has to be -1/2. Since the slope is 3, the slope of the equation you are making is -1/3. using desmos.com, I found out that the y-intercept has to be -1, so the equation is y=-1/3x-1

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3. Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10)

Artemon [7]

<u>Answer:</u>

$y = -\frac{1}{6}x +\frac{31}{3}$

<u>Step-by-step explanation:</u>

We are to find the equation for the line which is perpendicular to another line with the equation $y = 6x - 5$ and passes through a point (2, 10).

Since the slope of a line which is perpendicular to another line is the negative reciprocal of the other line, therefore the slope of our line will be $-\frac{1}{6}$ .