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algol13
2 years ago
12

What is the 5th equivalent fraction to 1 8 ?

Mathematics
1 answer:
valkas [14]2 years ago
7 0

Answer:

5/40

Step-by-step explanation:

1/8 = 2/16 = 3/24 = 4/32 = 5/40

you just need to add 1 to the numerator(number on top) and 8 to the denominator(number at bottom). :)

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Landen spent L hours at the beach last weekend. Matéo spent 15% fewer hours at the beach than Landen did
fenix001 [56]

Answer: B, D, and E

0.85L

or

L-0.15L

or

L(1-0.15)

or

L - \frac{15}{100}L

L - \frac{3}{20}L

Step-by-step explanation:

L is the number of hours Landen spent at the beach. Mateo spent 15% less time. This means he spent 85% of it. So 0.85 times L. We can also calculate it by subtracting the difference between the two kids. - 15%. 15% is 0.15L or \frac{15}{100}L. We subtract by L-0.15L or as L - \frac{15}{100}L. This fraction can simplify to L - \frac{3}{20}L

4 0
2 years ago
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"A grain silo is shown below.
Phantasy [73]
V = r² π h + 1/2 · 4/3 r³ π 
V = 6² · 22/7 · 198 + 4/6 · 6³ · 22/7
V = 36 · 22 · 24 + 144 · 22/7 = 19,008 + 452.57 = 19,460.57 ≈ 19,461 ft³
Answer: B ) 19,461 ft³
4 0
3 years ago
the area of a trapezoid is 780 cm squared. the shorter base is 48 cm and the height is 15 cm. Find the length of the other base
Anna35 [415]
If you multiply 48cm times 15cm,you get 720cm.Which would leave you with 60 left because 780 minus 720 equals 60.The height of the other base is 60cm.
6 0
3 years ago
Plz answer this promise you will get point tysm! Thank you a millions times!
zhenek [66]
I think 4. is 2 and 4. but I'm not entirely sure because I haven't done factors in a long time.
8 0
3 years ago
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Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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